Aptitude - Simplification

11.

20 + 8 x 0.520 − p = 12

Answer

Answer :

Option C

Explanation :


Given expression : 20 + 420 − p = 12
240 − 12p = 24 12p = (240 − 24) = 216
p = 18
12.

9 − 129 of 3311 ÷ 517 of 79 =

Answer

Answer :

Option B

Explanation :


Given expression = 9 − 119 of 3611 ÷ 367 of 79 = 9 − 4 ÷ 4 = 9 − 1 = 8
13.

If a + b + c = 11 and ab + bc + ca = 20, then (a3 + b3 + c3 − 3abc) =

Answer

Answer :

Option C

Explanation :


(a3 + b3 + c3 − 3abc)
= (a + b + c)( a2 + b2 + c2abbcca)
= (a + b + c)[(a + b + c)2 − 3(ab + bc + ca)]
= 11 x [(11)2 − 3 x 20] = 11 x (121 − 60) = 11 x 61 = 671
14.

11 + 11 + 1p = 2, then p =

Answer

Answer :

Option A

Explanation :


11 + 11 + 1p = 2
11 + p1 + p = 2
(p + 1)(2p + 1) = 2
p + 1 = 4p + 2 3p = −1
p = −13
15.

How many 18's are there in 3712?

Answer

Answer :

Option A

Explanation :


Reqd. number = 752 ÷ 18 = 752 x 8 = 300
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