Aptitude - Average
1.
Find the average of first five multiples of 3.
Answer
Given numbers are : 3, 6, 9, 12, 15
Average = 3 + 6 + 9 + 12 +155 = 455 = 9
Answer :
Option BExplanation :
Given numbers are : 3, 6, 9, 12, 15
Average = 3 + 6 + 9 + 12 +155 = 455 = 9
2.
The average of 25 terms is 18. The average of first 12 of them is 14 and that of last 12 terms is 17. Find the 13th term.
Answer
13th term = Sum of 25 terms − Sum of 24 terms except 13th
= (18 x 25 ) − [(14 x 12) + (17 x 12)]
= 450 − (168 + 204) = (450 − 372) = 78
Answer :
Option DExplanation :
13th term = Sum of 25 terms − Sum of 24 terms except 13th
= (18 x 25 ) − [(14 x 12) + (17 x 12)]
= 450 − (168 + 204) = (450 − 372) = 78
3.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs ?
Answer
Required run rate = 282 − (3.2 x 10) 40 = 250 40 = 6.25
Answer :
Option AExplanation :
Required run rate = 282 − (3.2 x 10) 40 = 250 40 = 6.25
4.
If 16a + 16b = 48, what is the average of a and b ?
Answer
16a + 16b = 48 ⇒ 16(a + b) = 48 ⇒ a + 16b = 3
Average of a and b = a + b 2 = 3 2 = 1.5
Answer :
Option AExplanation :
16a + 16b = 48 ⇒ 16(a + b) = 48 ⇒ a + 16b = 3
Average of a and b = a + b 2 = 3 2 = 1.5
5.
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is :
Answer
Total weight of A, B, C = (45 x 3) kg = 135 kg.
Total weight of A and B = (40 x 2) kg = 80 kg.
Total weight of B and C = (43 x 2) kg = 86 kg.
Weight of B = (80 + 86 − 135) kg = 31 kg.
Answer :
Option DExplanation :
Total weight of A, B, C = (45 x 3) kg = 135 kg.
Total weight of A and B = (40 x 2) kg = 80 kg.
Total weight of B and C = (43 x 2) kg = 86 kg.
Weight of B = (80 + 86 − 135) kg = 31 kg.
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