Aptitude - Time and Distance
1.
A train travels at 82.6 kmph. How many meters will it travel in 15 minutes ?
Answer
82.6 kmph =
82.6 x 518 
m/sec = 41318 m/sec
Distance covered in 15 minutes = 41318 x 15 x 60 m = 20650 m
Answer :
Option DExplanation :
82.6 kmph =
82.6 x 518 m/sec = 41318 m/secDistance covered in 15 minutes =
41318 x 15 x 60 m = 20650 m 2.
A is twice as fast as B and B is thrice as fast as C. The journey covered by C in 42 minutes will be covered by A in
Answer
Let C's speed be x metres/min.
Let time taken by A be y min.
Then, B's speed = 3x metres/min and A's speed = 6x metres/min.
Ratio of speeds of A and C = Ratio of time taken by C and A
6x : x = 42 : y ⇒ 6xx = 42y
⇒ y = 426 min = 7 min.
Answer :
Option AExplanation :
Let C's speed be x metres/min.
Let time taken by A be y min.
Then, B's speed = 3x metres/min and A's speed = 6x metres/min.
Ratio of speeds of A and C = Ratio of time taken by C and A
6x : x = 42 : y ⇒ 6xx = 42y
⇒ y = 426 min = 7 min.
3.
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 kmph and partly on bicycle at 9 kmph. The distance travelled on foot is :
Answer
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 − x) km.
∴ x4 + 61 − x9 = 9 ⇒ 9x + 4(61 − x) = 324
⇒ 5x = (324 − 244) = 80 ⇒ x = 16
Distance covered on foot = 16 km.
Answer :
Option CExplanation :
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 − x) km.
∴ x4 + 61 − x9 = 9 ⇒ 9x + 4(61 − x) = 324
⇒ 5x = (324 − 244) = 80 ⇒ x = 16
Distance covered on foot = 16 km.
4.
The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 5 hours, then the speed of the first train is :
Answer
Let the speed of first train be 7x kmph.
Then, the speed of the second train is 8x kmph.
But, speed of second train = 4005 kmph = 80 kmph
∴ 8x = 80 ⇒ x = 10
Hence, speed of 1st train is (7 x 10) kmph = 70 kmph.
Answer :
Option AExplanation :
Let the speed of first train be 7x kmph.
Then, the speed of the second train is 8x kmph.
But, speed of second train = 4005 kmph = 80 kmph
∴ 8x = 80 ⇒ x = 10
Hence, speed of 1st train is (7 x 10) kmph = 70 kmph.
5.
If a person walks at 14 kmph instead of 10 kmph, he would have walked 20 km more. The actual distance travelled by him is :
Answer
Let the actual distance travelled be x km.
Then, x10 = x + 2014
⇒ 14x = 10x + 200 ⇒ 4x = 200
⇒ x = 50 km
Answer :
Option DExplanation :
Let the actual distance travelled be x km.
Then, x10 = x + 2014
⇒ 14x = 10x + 200 ⇒ 4x = 200
⇒ x = 50 km
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